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# Understanding basic electrical math for troubleshooting series and parallel circuits ### Amps = I (Intensity) (Current)

• I = E/R
• The current (Amps)(Intensity) is equal at each load in a series circuit
• To find the Amps in a series circuit: Combine the total resistance for each load in series (TTL_R = R_a + R_b + R_c ....), divide applied voltage by total resistance (I=E/TTL_R), and current is equal (same) at every load.
• The current (Amps)(Intensity) varies (I=E/R) for each load in a parallel circuit ### Volts = E (Electromotive Force)

• E = I * R
• Voltage across a parallel circuit is equal to each load
• Voltage through a series drops at each load
• To find Voltage drop through a series circuit:
• Total R (resistance) of series circuitÂ Â  | TTL_R = R_a + R_b + R_c
• Divide V (volts) by total R (resistance) | I = V - TTL_R
• Left with I (current)
• Apply I (current) to every R (resistance) per load | V_a = I * R_a, V_b = I * R_b, â€¦
• At each load Voltage Drop = R (resistance) * I (current)
• The sum of the voltage drop is always equal to the amount of applied voltage

Color on diagram below depicts voltage weakening and not a comparison of voltage drops. ### Ohms = R (Resistance)

• R = E / I
• Sum of resistance (3 circuits in example) in parallel is = 1/( (1/X) + (1/Y) +(1/Z) )
• Sum of resistance (3 circuits in example) in series is = X + Y + Z • W = I * E